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0=4+21.5x-4.9x^2
We move all terms to the left:
0-(4+21.5x-4.9x^2)=0
We add all the numbers together, and all the variables
-(4+21.5x-4.9x^2)=0
We get rid of parentheses
4.9x^2-21.5x-4=0
a = 4.9; b = -21.5; c = -4;
Δ = b2-4ac
Δ = -21.52-4·4.9·(-4)
Δ = 540.65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21.5)-\sqrt{540.65}}{2*4.9}=\frac{21.5-\sqrt{540.65}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21.5)+\sqrt{540.65}}{2*4.9}=\frac{21.5+\sqrt{540.65}}{9.8} $
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